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  4. A 10 m long iron chain of linear mass density 0.8 kg m -1 is hanging freely from a rigid support. If g =10 ms -2, then the power required to left the chain upto the point of support in 10 second

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Q. A $10 \,m$ long iron chain of linear mass density $0.8 \,kg \,m ^{-1}$ is hanging freely from a rigid support. If $g =10 \,ms ^{-2}$, then the power required to left the chain upto the point of support in $10$ second

Work, Energy and Power

Solution:

$m =10 \times 0.8 \,kg =8 \,kg$
height of iron chain $=5 \, m$
$P =\frac{ mgh }{ t }=\frac{8 \times 10 \times 5}{10} W =40\, W$