A 10 H.P motor pumps out water from a well of depth 20 m and fills a water tank of volume 22380 litres at a height of 10 m from ground. The running time of the motor to fill the empty water tank is ( g =10 m / s 2)

Question

A 10 H.P motor pumps out water from a well of depth 20 m and fills a water tank of volume 22380 litres at a height of 10 m from ground. The running time of the motor to fill the empty water tank is ( g =10 m / s 2) (A) 5 minutes (B) 10 minutes (C) 15 minutes (D) 20 minutes

Tardigrade Admin · Accepted Answer

p =(W/t)=(m g (h1+h2)/t) t =(22380 × 10-3 × 103 × 10(20+10)/10 × 746 × 60)

Q. A $10 H . P$ motor pumps out water from a well of depth $20 m$ and fills a water tank of volume $22380$ litres at a height of $10 m$ from ground. The running time of the motor to fill the empty water tank is $(g = 10 m / s^{2})$

5 minutes

10 minutes

15 minutes

20 minutes

$p = \frac{W}{t} = \frac{m g ( h _{1} + h _{2} )}{t}$
$t = \frac{22380 \times 1 0 ^{- 3} \times 1 0 ^{3} \times 10 ( 20 + 10 )}{10 \times 746 \times 60}$

Q. A 10H.P motor pumps out water from a well of depth 20m and fills a water tank of volume 22380 litres at a height of 10m from ground. The running time of the motor to fill the empty water tank is (g=10m/s2)