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  4. A 10 H.P motor pumps out water from a well of depth 20 m and fills a water tank of volume 22380 litres at a height of 10 m from ground. The running time of the motor to fill the empty water tank is ( g =10 m / s 2)

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Q. A $10\, H.P$ motor pumps out water from a well of depth $20\, m$ and fills a water tank of volume $22380$ litres at a height of $10\, m$ from ground. The running time of the motor to fill the empty water tank is $\left( g =10\, m / s ^{2}\right)$

Solution:

$p =\frac{W}{t}=\frac{m g\,\left(h_{1}+h_{2}\right)}{t}$
$t =\frac{22380 \times 10^{-3} \times 10^{3} \times 10(20+10)}{10 \times 746 \times 60}$