A 1 kg particle strikes a wall with velocity 1 m / s at an angle of 60° with the wall and reflects at the same angle. If it remains in contact with wall for 0.1 s, then the force is

Question

A 1 kg particle strikes a wall with velocity 1 m / s at an angle of 60° with the wall and reflects at the same angle. If it remains in contact with wall for 0.1 s, then the force is (A) 0 (B) 10 √3 N (C) 30 √3 N (D) 40 √3 N

Tardigrade Admin · Accepted Answer

As it is clear from figure, F=( text change in momentum / text time )=(2 m v sin θ/t) =(2 × 1 × 1 × sin 60°/0.1)=10 √3 N <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/7fd32bf2cbdb05c444b542dfd11d8b05-.png" />

Q. A $1 k g$ particle strikes a wall with velocity $1 m / s$ at an angle of $6 0^{\circ}$ with the wall and reflects at the same angle. If it remains in contact with wall for $0.1 s$ , then the force is

$0$

$103 N$

$303 N$

$403 N$

As it is clear from figure,
$F = \frac{change in momentum}{time} = \frac{2 m v s i n θ}{t}$
$= \frac{2 \times 1 \times 1 \times s i n 6 0 ^{\circ}}{0.1} = 103 N$

Q. A 1kg particle strikes a wall with velocity 1m/s at an angle of 60∘ with the wall and reflects at the same angle. If it remains in contact with wall for 0.1s, then the force is

0

103​N

303​N

403​N

As it is clear from figure, F= time change in momentum ​=t2mvsinθ​ =0.12×1×1×sin60∘​=103​N

Q. A $1 k g$ particle strikes a wall with velocity $1 m / s$ at an angle of $6 0^{\circ}$ with the wall and reflects at the same angle. If it remains in contact with wall for $0.1 s$ , then the force is

$0$

$103 N$

$303 N$

$403 N$

As it is clear from figure,
$F = \frac{change in momentum}{time} = \frac{2 m v s i n θ}{t}$
$= \frac{2 \times 1 \times 1 \times s i n 6 0 ^{\circ}}{0.1} = 103 N$