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  4. A 1 kg particle strikes a wall with velocity 1 m / s at an angle of 60° with the wall and reflects at the same angle. If it remains in contact with wall for 0.1 s, then the force is

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Q. A $1\, kg $ particle strikes a wall with velocity $1\, m / s$ at an angle of $60^{\circ}$ with the wall and reflects at the same angle. If it remains in contact with wall for $0.1\, s$, then the force is

Laws of Motion

Solution:

As it is clear from figure,
$F=\frac{\text { change in momentum }}{\text { time }}=\frac{2 m v \sin \theta}{t}$
$=\frac{2 \times 1 \times 1 \times \sin 60^{\circ}}{0.1}=10 \sqrt{3} N$
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