A 1 kg block and a 0.5 kg block move together on a horizontal frictionless surface. Each block exerts a force of 6 N on the other. The blocks move with a uniform acceleration of

Question

A 1 kg block and a 0.5 kg block move together on a horizontal frictionless surface. Each block exerts a force of 6 N on the other. The blocks move with a uniform acceleration of <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/c45f0f6914267420dd8c9486681441cf-.png" /> (A) 3 ms -2 (B) 6 ms -2 (C) 9 ms -2 (D) 12 ms -2

Tardigrade Admin · Accepted Answer

As the contact force between the blocks is 6 N, the F.B.D. of the blocks is <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/93a4e0c5ed0b2fd2e197d3ad5bb543fe-.png" /> F-6=1 a and 6=0.5 a ⇒ a=(6/0.5)=12 m / s 2

Q. A $1 k g$ block and a $0.5 k g$ block move together on a horizontal frictionless surface. Each block exerts a force of $6 N$ on the other. The blocks move with a uniform acceleration of

$3 m s^{- 2}$

$6 m s^{- 2}$

$9 m s^{- 2}$

$12 m s^{- 2}$

As the contact force between the blocks is $6 N,$ the $F . B . D .$ of the blocks is

$F - 6 = 1 a$ and $6 = 0.5 a \Rightarrow a = \frac{6}{0.5} = 12 m / s^{2}$

Q. A 1kg block and a 0.5kg block move together on a horizontal frictionless surface. Each block exerts a force of 6N on the other. The blocks move with a uniform acceleration of

3ms−2

6ms−2

9ms−2

12ms−2