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Q. A $1\, kg$ block and a $0.5\, kg$ block move together on a horizontal frictionless surface. Each block exerts a force of $6 \,N$ on the other. The blocks move with a uniform acceleration of
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Laws of Motion

Solution:

As the contact force between the blocks is $6 N,$ the $F.B.D. $ of the blocks is
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$F-6=1 a$ and $6=0.5 a \Rightarrow a=\frac{6}{0.5}=12 \,m / s ^{2}$