A 1.00 × 10-20 kg particle is vibrating with simple harmonic motion with a period of 1.00 × 10-5 s and a maximum speed of 1.00 × 103 m / s. The maximum displacement of the particle is

Question

A 1.00 × 10-20 kg particle is vibrating with simple harmonic motion with a period of 1.00 × 10-5 s and a maximum speed of 1.00 × 103 m / s. The maximum displacement of the particle is (A) 1.59 mm (B) 1.00 cm (C) 10 m (D) None of these

Tardigrade Admin · Accepted Answer

v max =1 × 103 =a × (2 π/T) ⇒ a =(v max × T/2 π) a =(1 × 103 × 1 × 10-5/2 π)=1.59 mm

Q. A $1.00 \times 1 0^{- 20} k g$ particle is vibrating with simple harmonic motion with a period of $1.00 \times 1 0^{- 5} s$ and a maximum speed of $1.00 \times 1 0^{3} m / s$ . The maximum displacement of the particle is

1.59 mm

1.00 cm

10 m

None of these

$v_{m a x} = 1 \times 1 0^{3} = a \times \frac{2 π}{T}$
$\Rightarrow a = \frac{v _{m a x} \times T}{2 π}$
$a = \frac{1 \times 1 0 ^{3} \times 1 \times 1 0 ^{- 5}}{2 π} = 1.59 mm$

Q. A 1.00×10−20kg particle is vibrating with simple harmonic motion with a period of 1.00×10−5s and a maximum speed of 1.00×103m/s. The maximum displacement of the particle is