A 0.5 kg ball is thrown up with an initial speed 14 m / s and reaches a maximum height of 8.0 cm. How much energy is dissipated by air drag acting on the ball during the time of ascent?

Question

A 0.5 kg ball is thrown up with an initial speed 14 m / s and reaches a maximum height of 8.0 cm. How much energy is dissipated by air drag acting on the ball during the time of ascent? (A) 19.6 J (B) 4.9 J (C) 10 J (D) 9.8 J

Tardigrade Admin · Accepted Answer

If there is no air drag then maximum height H=(u2/2 g)=(14 × 14/2 × 9.8)=10 m But due to air drag ball reaches up to height 8 m only so, loss of energy =M g(10-8)=0.5 × 9.2 × 2=9.8 J

Q. A $0.5 k g$ ball is thrown up with an initial speed $14 m / s$ and reaches a maximum height of $8.0 c m$ . How much energy is dissipated by air drag acting on the ball during the time of ascent?

19.6 J

4.9 J

10 J

9.8 J

If there is no air drag then maximum height
$H = \frac{u ^{2}}{2 g} = \frac{14 \times 14}{2 \times 9.8} = 10 m$
But due to air drag ball reaches up to height $8 m$ only so, loss of energy
$= M g (10 - 8) = 0.5 \times 9.2 \times 2 = 9.8 J$

Q. A 0.5kg ball is thrown up with an initial speed 14m/s and reaches a maximum height of 8.0cm. How much energy is dissipated by air drag acting on the ball during the time of ascent?