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Q. A $0.5\, kg$ ball is thrown up with an initial speed $14\, m / s$ and reaches a maximum height of $8.0 \,cm$. How much energy is dissipated by air drag acting on the ball during the time of ascent?

Work, Energy and Power

Solution:

If there is no air drag then maximum height
$H=\frac{u^{2}}{2 g}=\frac{14 \times 14}{2 \times 9.8}=10\, m$
But due to air drag ball reaches up to height $8 \,m$ only so, loss of energy
$=M g(10-8)=0.5 \times 9.2 \times 2=9.8 \,J$