A 0.5 g/l solution of glucose is found to be isotonic with a 2.5 g/l solution of an organic compound. What will be the molecular weight of that organic compound?

Question

A 0.5 g/l solution of glucose is found to be isotonic with a 2.5 g/l solution of an organic compound. What will be the molecular weight of that organic compound? (A) 300 (B) 600 (C) 900 (D) 1200

Tardigrade Admin · Accepted Answer

Molarity of glucose solution =(0.5 g/180 × 1 lit)=0.0027 M Isotonic solution have equal molar concentration, hence molarity of organic compound solution =0.0027 M ∴ Molecular weight of compound =(2.5/0.0027 × 1)=900

Q. A $0.5 g / l$ solution of glucose is found to be isotonic with a $2.5 g / l$ solution of an organic compound. What will be the molecular weight of that organic compound?

300

600

900

1200

Molarity of glucose solution $= \frac{0.5 g}{180 \times 1 l i t} = 0.0027 M$ Isotonic solution have equal molar concentration, hence molarity of organic compound solution $= 0.0027 M$
$∴$ Molecular weight of compound
$= \frac{2.5}{0.0027 \times 1} = 900$

Q. A 0.5g/l solution of glucose is found to be isotonic with a 2.5g/l solution of an organic compound. What will be the molecular weight of that organic compound?

300

600

900

1200

Molarity of glucose solution =180×1lit0.5g​=0.0027M Isotonic solution have equal molar concentration, hence molarity of organic compound solution =0.0027M ∴ Molecular weight of compound =0.0027×12.5​=900

Q. A $0.5 g / l$ solution of glucose is found to be isotonic with a $2.5 g / l$ solution of an organic compound. What will be the molecular weight of that organic compound?

Molarity of glucose solution $= \frac{0.5 g}{180 \times 1 l i t} = 0.0027 M$ Isotonic solution have equal molar concentration, hence molarity of organic compound solution $= 0.0027 M$
$∴$ Molecular weight of compound
$= \frac{2.5}{0.0027 \times 1} = 900$