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Q. A $ 0.5\,g/l $ solution of glucose is found to be isotonic with a $ 2.5\,g/l $ solution of an organic compound. What will be the molecular weight of that organic compound?

Haryana PMTHaryana PMT 2003

Solution:

Molarity of glucose solution $=\frac{0.5\, g}{180 \times 1 lit}=0.0027\, M$ Isotonic solution have equal molar concentration, hence molarity of organic compound solution $=0.0027\, M$
$\therefore $ Molecular weight of compound
$=\frac{2.5}{0.0027 \times 1}=900$