A 0.5 g / L solution of glụcose is found to be isotonic with a 2.5 g / L solution of an organic compound. What will be the molecular weight of that organic compound?

Question

A 0.5 g / L solution of glụcose is found to be isotonic with a 2.5 g / L solution of an organic compound. What will be the molecular weight of that organic compound? (A) 300 (B) 600 (C) 900 (D) 200

Tardigrade Admin · Accepted Answer

Molarity of glucose solution =(0.58/180 × 1 L )=0.00277 M Isotonic solution have equal molar concentrations, hence molarity of organic compound solution =0.00277 M ∴ Molecular weight of compound =(2.5/0.00277 × 1)=900

Q. A $0.5 g / L$ solution of glụcose is found to be isotonic with a $2.5 g / L$ solution of an organic compound. What will be the molecular weight of that organic compound?

300

600

900

200

Molarity of glucose solution
$= \frac{0.58}{180 \times 1 L} = 0.00277 M$
Isotonic solution have equal molar concentrations, hence molarity of organic compound solution $= 0.00277 M$
$∴$ Molecular weight of compound
$= \frac{2.5}{0.00277 \times 1} = 900$

Q. A 0.5g/L solution of glụcose is found to be isotonic with a 2.5g/L solution of an organic compound. What will be the molecular weight of that organic compound?

300

600

900

200

Molarity of glucose solution =180×1L0.58​=0.00277M Isotonic solution have equal molar concentrations, hence molarity of organic compound solution =0.00277M ∴ Molecular weight of compound =0.00277×12.5​=900

Q. A $0.5 g / L$ solution of glụcose is found to be isotonic with a $2.5 g / L$ solution of an organic compound. What will be the molecular weight of that organic compound?

Molarity of glucose solution
$= \frac{0.58}{180 \times 1 L} = 0.00277 M$
Isotonic solution have equal molar concentrations, hence molarity of organic compound solution $= 0.00277 M$
$∴$ Molecular weight of compound
$= \frac{2.5}{0.00277 \times 1} = 900$