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Q. A $0.5\, g / L$ solution of glụcose is found to be isotonic with a $2.5\, g / L$ solution of an organic compound. What will be the molecular weight of that organic compound?

JIPMERJIPMER 2009Solutions

Solution:

Molarity of glucose solution
$=\frac{0.58}{180 \times 1\, L }=0.00277\, M$
Isotonic solution have equal molar concentrations, hence molarity of organic compound solution $=0.00277\, M$
$\therefore $ Molecular weight of compound
$=\frac{2.5}{0.00277 \times 1}=900$