75 mL of H 2 SO 4 (specific gravity 1.18 ) containing 49 % H 2 SO 4 by mass is diluted to 590 mL. Calculate molarity of the diluted solution. [At. wt.: S =32 ]

Question

75 mL of H 2 SO 4 (specific gravity 1.18 ) containing 49 % H 2 SO 4 by mass is diluted to 590 mL. Calculate molarity of the diluted solution. [At. wt.: S =32 ] (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

M1 V1=M2 V2 (7.5 × 1.18 × 49 × 10/98)=M2 × 590

Q. $75 m L$ of $H_{2} S O_{4}$ (specific gravity $1.18$ ) containing $49%$ $H_{2} S O_{4}$ by mass is diluted to $590 m L$ . Calculate molarity of the diluted solution. [At. wt.: $S = 32$ ]

$M_{1} V_{1} = M_{2} V_{2}$
$\frac{7.5 \times 1.18 \times 49 \times 10}{98} = M_{2} \times 590$

Q. 75mL of H2​SO4​ (specific gravity 1.18 ) containing 49% H2​SO4​ by mass is diluted to 590mL. Calculate molarity of the diluted solution. [At. wt.: S=32 ]

M1​V1​=M2​V2​ 987.5×1.18×49×10​=M2​×590

Q. $75 m L$ of $H_{2} S O_{4}$ (specific gravity $1.18$ ) containing $49%$ $H_{2} S O_{4}$ by mass is diluted to $590 m L$ . Calculate molarity of the diluted solution. [At. wt.: $S = 32$ ]

$M_{1} V_{1} = M_{2} V_{2}$
$\frac{7.5 \times 1.18 \times 49 \times 10}{98} = M_{2} \times 590$