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  3. Chemistry
  4. 75 mL of H 2 SO 4 (specific gravity 1.18 ) containing 49 % H 2 SO 4 by mass is diluted to 590 mL. Calculate molarity of the diluted solution. [At. wt.: S =32 ]

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Q. $75 \,mL$ of $H _{2} SO _{4}$ (specific gravity $1.18$ ) containing $49 \%$ $H _{2} SO _{4}$ by mass is diluted to $590 \,mL$. Calculate molarity of the diluted solution. [At. wt.: $S =32$ ]

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Solution:

$M_{1} V_{1}=M_{2} V_{2}$
$\frac{7.5 \times 1.18 \times 49 \times 10}{98}=M_{2} \times 590$