Question

$6.3g$ of oxalic acid dihydrate (molar mass $=126.07g/mol)$ is diluted to form an aqueous solution of $250mL$. Find the volume of $0.1NNaOH$ required to completely neutralize $10mL$ of this solution.

• A. 40 mL
• B. 20 mL
• C. 10 mL
• D. 4 mL

Answer 1

Answer: (A)

Normality $=\frac{\frac{g}{\text{equivalent weight}}}{V\left(mL\right)}\times 1000$
Equivalent weight of oxalic acid dihydrate $=63$
Normality $=\frac{\frac{6.3}{63}}{250}\times 1000=0.4N$
Now using $N_1{V}_1=N_2{V}_2$
$N_1=0.4$ , $V_1=10mL$ , $N_2=0.1$ , $V_2=?$
$V_2=\frac{N_1{V}_1}{N_2}=\frac{0.4\times 10}{0.1}=40mL$