Question

$6.3 \,g$ of oxalic acid dihydrate (molar mass $= 126.07\, g/mol)$ is diluted to form an aqueous solution of $250\, mL$. Find the volume of $0.1 \,N\, NaOH$ required to completely neutralize $10 \,mL$ of this solution.

• A. 40 mL
• B. 20 mL
• C. 10 mL
• D. 4 mL

Answer 1

Answer: (A)

Normality $=\frac{\frac{g}{\text{equivalent weight}}}{V \left(m L\right)}\times 1000$
Equivalent weight of oxalic acid dihydrate $= 63$
Normality $=\frac{\frac{6.3}{63}}{250}\times 1000=0.4 \, N$
Now using $N_{1}V_{1}=N_{2}V_{2}$
$N_{1}=0.4$ , $V_{1}=10 \, mL$ , $N_{2}=0.1$ , $V_{2}=?$
$V_{2}=\frac{N_{1} V_{1}}{N_{2}}=\frac{0.4 \times 10}{0.1}=40 \, mL$