50 ml 10 N-H2SO4 , 25 ml 12N-HCl and 40 ml 5N-HNO3 were mixed together and the volume of the mixture was made 1000 ml by adding water. The normality of the resultant solution will be

Question

50 ml 10 N-H2SO4 , 25 ml 12N-HCl and 40 ml 5N-HNO3 were mixed together and the volume of the mixture was made 1000 ml by adding water. The normality of the resultant solution will be (A) 1 textN (B) 2 textN (C) 3 textN (D) 4 textN

Tardigrade Admin · Accepted Answer

underset textN1 textV1 + textN2 textV2 + textN3 textV3 = textN × 1000 textm textl textH2 textS textO4 textH textC textl textH textN textO3 textT texto textt texta textl textv texto textl textu textm texte textN=( textN1 textV1 + textN2 textV2 + textN3 textV3/1000) =(50 × 10 + 25 × 12 + 40 × 5/1000) textN=(500 + 300 + 200/1000)=(1000/1000)=1 textN

Q. $50 m l 10 N - H_{2} S O_{4}$ , $25 m l$ $12 N - H Cl$ and $40 m l$ $5 N - H N O_{3}$ were mixed together and the volume of the mixture was made $1000 m l$ by adding water. The normality of the resultant solution will be

$1 N$

$2 N$

$3 N$

$4 N$

Q. 50ml10N−H2​SO4​ , 25ml 12N−HCl and 40ml 5N−HNO3​ were mixed together and the volume of the mixture was made 1000ml by adding water. The normality of the resultant solution will be

1N

2N

3N

4N

N1​V1​+N2​V2​+N3​V3​=N×1000mlH2​SO4​HClHNO3​Totalvolume​ N=1000N1​V1​+N2​V2​+N3​V3​​ =100050×10+25×12+40×5​ N=1000500+300+200​=10001000​=1N

Q. $50 m l 10 N - H_{2} S O_{4}$ , $25 m l$ $12 N - H Cl$ and $40 m l$ $5 N - H N O_{3}$ were mixed together and the volume of the mixture was made $1000 m l$ by adding water. The normality of the resultant solution will be

$1 N$

$2 N$

$3 N$

$4 N$