Question

$50 \, ml \, 10 \, N-H_{2}SO_{4}$ , $25 \, ml$ $12N-HCl$ and $40 \, ml$ $5N-HNO_{3}$ were mixed together and the volume of the mixture was made $1000 \, ml$ by adding water. The normality of the resultant solution will be

• A. $1 \, \text{N}$
• B. $2 \, \text{N}$
• C. $3 \, \text{N}$
• D. $4 \, \text{N}$

Answer 1

Answer: (A)

$\underset{ \, \, \text{N}_{1} \text{V}_{1} \, \, \, + \, \, \text{N}_{2} \text{V}_{2} \, + \, \, \, \text{N}_{3} \text{V}_{3} \, \, \, = \, \text{N} \, \times \, 1000 \, \, \text{m} \text{l} \, \, \, }{\text{H}_{2} \text{S} \text{O}_{4} \, \text{H} \text{C} \text{l} \, \, \, \text{H} \text{N} \text{O}_{3} \, \text{T} \text{o} \text{t} \text{a} \text{l} \, \text{v} \text{o} \text{l} \text{u} \text{m} \text{e}}$

$\text{N}=\frac{\text{N}_{1} \text{V}_{1} + \text{N}_{2} \text{V}_{2} + \text{N}_{3} \text{V}_{3}}{1000}$

$=\frac{50 \times 10 + 25 \times 12 + 40 \times 5}{1000}$

$\text{N}=\frac{500 + 300 + 200}{1000}=\frac{1000}{1000}=1 \, \text{N}$