50 gm ice at 0° C in insulator vessel, 50 g water of 100° C is mixed in it, then final temperature of the mixture is (neglect the heat loss):

Question

50 gm ice at 0° C in insulator vessel, 50 g water of 100° C is mixed in it, then final temperature of the mixture is (neglect the heat loss): (A)  10° C  (B)  0° < < Tm < 20° C (C)  20° C  (D) Above 20° C

Tardigrade Admin · Accepted Answer

According to galvanometer principle, heat given =heat taken m1 s1(100-t) =m L +m2 s2(t-0) 50 × 1(100-t) =50 × 80+50 × 1(t-0) t =10° C

Q. $50 g m$ ice at $0^{\circ} C$ in insulator vessel, $50 g$ water of $10 0^{\circ} C$ is mixed in it, then final temperature of the mixture is (neglect the heat loss):

$1 0^{\circ} C$

$0^{\circ} << T_{m} < 2 0^{\circ} C$

$2 0^{\circ} C$

Above $2 0^{\circ} C$

According to galvanometer principle,
heat given =heat taken
$m_{1} s_{1} (100 - t) = m L + m_{2} s_{2} (t - 0)$
$50 \times 1 (100 - t) = 50 \times 80 + 50 \times 1 (t - 0)$
$t = 1 0^{\circ} C$

Q. 50gm ice at 0∘C in insulator vessel, 50g water of 100∘C is mixed in it, then final temperature of the mixture is (neglect the heat loss):

10∘C

0∘<<Tm​<20∘C

20∘C

Above 20∘C