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Q. $50\, gm$ ice at $0^{\circ} C$ in insulator vessel, $50\, g$ water of $100^{\circ} C$ is mixed in it, then final temperature of the mixture is (neglect the heat loss):

Rajasthan PMTRajasthan PMT 2001Thermal Properties of Matter

Solution:

According to galvanometer principle,
heat given =heat taken
$m_{1} s_{1}(100-t) =m L +m_{2} s_{2}(t-0)$
$50 \times 1(100-t) =50 \times 80+50 \times 1(t-0)$
$t =10^{\circ} C$