Question

$50g$ of saturated aqueous solution of potassium chloride at $30^{°}C$ is evaporated to dryness, When $13.2g$ of dry $KCl$ was obtained. The solubility of $KCl$ in water at $30^{°}C$ is

• A. $35.87g$
• B. $25.62g$
• C. $28.97g$
• D. $27.81g$

Answer 1

Answer: (A)

The solubility of a solute in a solvent at any temperature is defined as the maximum amount of the solute in grams which can dissolve in $100g$ of the solvent to form the saturated solution at that particular temperature.

Weight of solute $(KCl)=13.2g$

Weight of solvent $=50-13.2=36.8g$

$\therefore$ Solubility of $KCl=\frac{132}{36.3}\times 100=35.869$