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Q.
$50\, g$ of saturated aqueous solution of potassium chloride at $30^°C$ is evaporated to dryness, When $13.2\, g$ of dry $KCl$ was obtained. The solubility of $KCl$ in water at $30^°C$ is
The solubility of a solute in a solvent at any temperature is defined as the maximum amount of the solute in grams which can dissolve in $100 g$ of the solvent to form the saturated solution at that particular temperature.
Weight of solute $( KCl )=13.2 \,g$
Weight of solvent $=50-13.2=36.8 \,g$
$\therefore $ Solubility of $KCl=\frac{132}{36.3} \times 100=35.869$