50 g ice at 0° C is dropped into a calorimeter containing 100 g water at 30° C. If thermal capacity of calorimeter is zero then amount of ice left in the mixture at equilibrium is

Question

50 g ice at 0° C is dropped into a calorimeter containing 100 g water at 30° C. If thermal capacity of calorimeter is zero then amount of ice left in the mixture at equilibrium is (A) 12.5 g (B) 25 g (C) 20 g (D) 10 g

Tardigrade Admin · Accepted Answer

Heat required to bring 100 g of water from 30° C to 0° C will be Q=100 × 1 × 30=3000 cal ∴ Amount of ice that get melted =(3000/80)=37.5 g So amount left =12.5 g

Q. $50 g$ ice at $0^{\circ} C$ is dropped into a calorimeter containing $100 g$ water at $3 0^{\circ} C$ . If thermal capacity of calorimeter is zero then amount of ice left in the mixture at equilibrium is

12.5 g

25 g

20 g

10 g

Heat required to bring $100 g$ of water from $3 0^{\circ} C$ to $0^{\circ} C$ will be
$Q = 100 \times 1 \times 30 = 3000 c a l$
$∴$ Amount of ice that get melted $= \frac{3000}{80} = 37.5 g$
So amount left $= 12.5 g$

Q. 50g ice at 0∘C is dropped into a calorimeter containing 100g water at 30∘C. If thermal capacity of calorimeter is zero then amount of ice left in the mixture at equilibrium is