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Q. $50\, g$ ice at $0^{\circ} C$ is dropped into a calorimeter containing $100 \,g$ water at $30^{\circ} C$. If thermal capacity of calorimeter is zero then amount of ice left in the mixture at equilibrium is

Thermal Properties of Matter

Solution:

Heat required to bring $100 \,g$ of water from $30^{\circ} C$ to $0^{\circ} C$ will be
$Q=100 \times 1 \times 30=3000\, cal$
$\therefore $ Amount of ice that get melted $=\frac{3000}{80}=37.5\, g$
So amount left $=12.5 \,g$