50.0 kg of N 2(g) and 10.0 kg of H 2(g) are mixed to produce NH 3(g). Identify the limiting reagent in the production of NH 3 in this situation.

Question

50.0 kg of N 2(g) and 10.0 kg of H 2(g) are mixed to produce NH 3(g). Identify the limiting reagent in the production of NH 3 in this situation. (A) Nitrogen (B) Hydrogen (C) Can't be predicted (D) None of these

Tardigrade Admin · Accepted Answer

underset1 mol 28 gN2+ underset3 mol 6 g3H2 → underset2 mol 34 g2NH3 (50,000/28)=1785.7 mol , (10,000/2)=5,000 mol 1 mol of N 2 requires 3 mol of hydrogen Thus, 1785.7 mol of N 2 will need 5357.1 mol of H 2. Thus, limiting reagent is H 2

Q. $50.0 k g$ of $N_{2 (g)}$ and $10.0 k g$ of $H_{2 (g)}$ are mixed to produce $N H_{3 (g)}$ . Identify the limiting reagent in the production of $N H_{3}$ in this situation.

Nitrogen

Hydrogen

Can't be predicted

None of these

$1 m o l 28 g N_{2} + 3 m o l 6 g 3 H_{2} \to 2 m o l 34 g 2 N H_{3}$

$\frac{50 , 000}{28} = 1785.7 m o l, \frac{10 , 000}{2} = 5, 000 m o l$

$1 m o l$ of $N_{2}$ requires 3 mol of hydrogen

Thus, $1785.7 m o l$ of $N_{2}$ will need $5357.1 m o l$ of $H_{2}$ .

Thus, limiting reagent is $H_{2}$

Q. 50.0kg of N2(g)​ and 10.0kg of H2(g)​ are mixed to produce NH3(g)​. Identify the limiting reagent in the production of NH3​ in this situation.