Question

$50.0\, kg$ of $N _{2(g)}$ and $10.0 \,kg$ of $H _{2(g)}$ are mixed to produce $NH _{3(g)}$. Identify the limiting reagent in the production of $NH _{3}$ in this situation.

• A. Nitrogen
• B. Hydrogen
• C. Can't be predicted
• D. None of these

Answer 1

Answer: (B)

$\underset{1\,mol\,28\,g}{N_{2}}+\underset{3\,mol\,6\,g}{3H_{2}} \to \underset{2\,mol\,34\,g}{2NH_{3}}$

$\frac{50,000}{28}=1785.7 \,mol , \frac{10,000}{2}=5,000\, mol$

$1 \,mol$ of $N _{2}$ requires 3 mol of hydrogen

Thus, $1785.7 mol$ of $N _{2}$ will need $5357.1 mol$ of $H _{2}$.

Thus, limiting reagent is $H _{2}$