5 textN textH2 textS textO4 was diluted from 1 textl texti textt textr texte to 10 textl texti textt textr texte texts . Normality of the solution obtained is

Question

5 textN textH2 textS textO4 was diluted from 1 textl texti textt textr texte to 10 textl texti textt textr texte texts . Normality of the solution obtained is (A) 10 textN (B) 5 textN (C) 1 textN (D) 0.5 textN

Tardigrade Admin · Accepted Answer

textN1 textV1= textN2 textV2 5 textN × 1 textl texti textt = textx × 10 textl texti textt. ∴ textx=0.5 textN

Q. $5 N$ $H_{2} S O_{4}$ was diluted from $1 l i t r e$ to $10 l i t r e s$ . Normality of the solution obtained is

$10 N$

$5 N$

$1 N$

$0.5 N$

$N_{1} V_{1} = N_{2} V_{2} 5 N \times 1 l i t = x \times 10 l i t .$
$∴$ $x = 0.5 N$

Q. 5N H2​SO4​ was diluted from 1litre to 10litres . Normality of the solution obtained is

10N

5N

1N

0.5N