Question

$5\text{N}$ $\text{H}_{2}\text{S}\text{O}_{4}$ was diluted from $1 \, \text{l}\text{i}\text{t}\text{r}\text{e}$ to $10 \, \text{l}\text{i}\text{t}\text{r}\text{e}\text{s}$ . Normality of the solution obtained is

• A. $10 \, \text{N}$
• B. $5 \, \text{N}$
• C. $1 \, \text{N}$
• D. $0.5 \, \text{N}$

Answer 1

Answer: (D)

$\text{N}_{1}\text{V}_{1}=\text{N}_{2}\text{V}_{2} \, \, 5\text{N} \, \times 1 \, \text{l}\text{i}\text{t} \, = \, \text{x} \, \times \, 10 \, \text{l}\text{i}\text{t}.$
$\therefore $ $\text{x}=0.5 \, \text{N}$