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Question
Chemistry
5 L of NaOH solution of pH 12 contains
Q.
5
L
of
N
a
O
H
solution of pH
12
contains
1882
218
COMEDK
COMEDK 2009
Equilibrium
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A
200 g
13%
B
0.2 g
23%
C
20 g
25%
D
2 g
39%
Solution:
pH of solution
=
12
Hence,
pO
H
=
14
−
12
=
2
⇒
[
O
H
−
]
=
1
0
−
2
m
o
l
/
L
1
L
contains
1
0
−
2
moles of
O
H
−
ions.
Hence,
5
L
will contain
5
×
1
0
−
2
moles of
O
H
−
ions.
Now, no. of moles =
m
o
l
.
ma
ss
w
w
=
5
×
1
0
−
2
×
40
=
2
g