4.5 g of compound A ( MW =90) was used to make 250 mL of its aqueous solution. The molarity of the solution in M is x × 10-1 . The value of x is . (Rounded off to the nearest integer)

Question

4.5 g of compound A ( MW =90) was used to make 250 mL of its aqueous solution. The molarity of the solution in M is x × 10-1 . The value of x is . (Rounded off to the nearest integer) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

M =(4.5 / 90/250 / 1000)=0.2 =2 × 10-1

Q. $4.5 g$ of compound $A (M W = 90)$ was used to make $250 m L$ of its aqueous solution. The molarity of the solution in $M$ is $x \times 1 0^{- 1} .$ The value of $x$ is ________. (Rounded off to the nearest integer)

$M = \frac{4.5/90}{250/1000} = 0.2$

$= 2 \times 1 0^{- 1}$

Q. 4.5g of compound A(MW=90) was used to make 250mL of its aqueous solution. The molarity of the solution in M is x×10−1. The value of x is ________. (Rounded off to the nearest integer)

M=250/10004.5/90​=0.2 =2×10−1

Q. $4.5 g$ of compound $A (M W = 90)$ was used to make $250 m L$ of its aqueous solution. The molarity of the solution in $M$ is $x \times 1 0^{- 1} .$ The value of $x$ is ________. (Rounded off to the nearest integer)

$M = \frac{4.5/90}{250/1000} = 0.2$

$= 2 \times 1 0^{- 1}$