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  4. 4.5 g of compound A ( MW =90) was used to make 250 mL of its aqueous solution. The molarity of the solution in M is x × 10-1 . The value of x is . (Rounded off to the nearest integer)

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Q. $4.5 g$ of compound $A ( MW =90)$ was used to make $250 mL$ of its aqueous solution. The molarity of the solution in $M$ is $x \times 10^{-1} .$ The value of $x$ is ________. (Rounded off to the nearest integer)

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Solution:

$M =\frac{4.5 / 90}{250 / 1000}=0.2$

$=2 \times 10^{-1}$