Question

$4.4$ grams of a gas at $0^{\circ }C$ and $0.82$ atm pressure occupies a volume of $2.73L$. The gascan be

• A. $O_2$
• B. $CO$
• C. $N{O}_2$
• D. $C{O}_2$

Answer 1

Answer: (D)

$4.4g$ of a gas at $\mathrm{STP}\left(0^{\circ }C\right)$ occupies a volume of $2.73L$
At STP, $1$ mole of any gas occupies a volume of $24.4L$.
$4.4g$ of a gas at STP occupies a volume of $2.73L$.
Hence, the number of moles of gas
$=\frac{22.4}{2.73}=0.1mol$
$0.1$ mole of a gas $=4.4g$
$1$ mole of a gas $=4.4\times \frac{1}{0.1}=44g$
Thus, the molecular weight of gas is $44g/mol$.
It is the molecular weight of $C{O}_2$ gas.