4.28 g of NaOH is dissolved in water and the solution is made to 250 cc. What will be the molarity of the solution?

Question

4.28 g of NaOH is dissolved in water and the solution is made to 250 cc. What will be the molarity of the solution? (A) 0.615 mol L-1 (B) 0.428 mol L-1 (C) 0.99 mol L-1 (D) 0.301 mol L-1

Tardigrade Admin · Accepted Answer

No. of moles of NaOH =(4.28/40) = 0.107 Volume of solution = 250 cm 3 M = ( n/V(in L)) = (0.107/250) × 1000 = 0.428 mol L-1

Q. $4.28 g$ of $N a O H$ is dissolved in water and the solution is made to $250 cc$ . What will be the molarity of the solution?

$0.615 m o l L^{- 1}$

$0.428 m o l L^{- 1}$

$0.99 m o l L^{- 1}$

$0.301 m o l L^{- 1}$

No. of moles of $N a O H = \frac{4.28}{40} = 0.107$
Volume of solution $= 250 c m^{3}$
$M = \frac{n}{V ( in L )} = \frac{0.107}{250} \times 1000 = 0.428 m o l L^{- 1}$

Q. 4.28g of NaOH is dissolved in water and the solution is made to 250cc. What will be the molarity of the solution?

0.615molL−1

0.428molL−1

0.99molL−1

0.301molL−1