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Chemistry
4.28 g of NaOH is dissolved in water and the solution is made to 250 cc. What will be the molarity of the solution?
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Q. $4.28 \,g$ of $NaOH$ is dissolved in water and the solution is made to $250 \,cc$. What will be the molarity of the solution?
Some Basic Concepts of Chemistry
A
$0.615\, mol L^{-1}$
25%
B
$0.428\, mol L^{-1}$
54%
C
$0.99\, mol L^{-1}$
15%
D
$0.301\, mol L^{-1}$
5%
Solution:
No. of moles of $NaOH =\frac{4.28}{40} = 0.107$
Volume of solution $= 250 cm ^{3}$
$ M = \frac { n}{V(in L)} = \frac{0.107}{250} \times 1000 = 0.428\, mol\, L^{-1}$