Question

$36g$ of glucose (molar mass $=180g/mol$ ) if present in $500g$ of water, the molality of the solution is

• A. 0.2
• B. 0.4
• C. 0.8
• D. 1.0

Answer 1

Answer: (B)

Molality, $m=\frac{\text{ moles of solute }\times 1000}{\text{ mass of solvent }(\text{ in }g)}$
$=\frac{36\times 1000}{180\times 500}=0.4m$