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  4. 36 g of glucose (molar mass =180 g/mol ) if present in 500 g of water, the molality of the solution is

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Q. $36\, g$ of glucose (molar mass $ =180\,g/mol $ ) if present in $500\,g$ of water, the molality of the solution is

J & K CETJ & K CET 2010Solutions

Solution:

Molality, $m =\frac{\text { moles of solute } \times 1000}{\text { mass of solvent }(\text { in } g )}$
$=\frac{36 \times 1000}{180 \times 500}=0.4\, m$