Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
36.5 % HCl has density equal to 1.20 g mL -1. The molarity ( M ) and molality (m), respectively, are
Q.
36.5%
H
Cl
has density equal to
1.20
g
m
L
−
1
. The molarity
(
M
)
and molality (m), respectively, are
1114
157
Some Basic Concepts of Chemistry
Report Error
A
15.7
,
15.7
14%
B
12
,
12
0%
C
15.7
,
12
43%
D
12
,
15.7
43%
Solution:
M
=
M
w
2
%
by weight
×
10
×
d
=
36.5
36.5
×
10
×
1.2
=
12
M
m
=
36.5
×
(
100
−
36.5
)
36.5
×
1000
=
63.5
1000
=
15.7
m