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  4. 36.5 % HCl has density equal to 1.20 g mL -1. The molarity ( M ) and molality (m), respectively, are

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Q. $36.5 \% HCl$ has density equal to $1.20\, g\, mL ^{-1}$. The molarity $( M )$ and molality (m), respectively, are

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Solution:

$M=\frac{\% \text { by weight } \times 10 \times d }{M w_2}=\frac{36.5 \times 10 \times 1.2}{36.5}$
$=12\, M$
$m=\frac{36.5 \times 1000}{36.5 \times(100-36.5)}=\frac{1000}{63.5}=15.7\, m$