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Tardigrade
Question
Chemistry
3 g of a hydrocarbon on combustion with excess of oxygen produces 8.8 g of CO 2 and 5.4 g of H 2 O The data illustrates the law of
Q.
3
g
of a hydrocarbon on combustion with excess of oxygen produces
8.8
g
of
C
O
2
and
5.4
g
of
H
2
O
The data illustrates the law of
1982
176
Some Basic Concepts of Chemistry
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A
conservation of mass
49%
B
multiple proportions
26%
C
constant proportions
14%
D
reciprocal proportions.
11%
Solution:
Amount of carbon in
8.8
g
C
O
2
=
12
×
number of moles of
C
O
2
=
44
12
×
8.8
=
2.4
g
Amount of hydrogen in
5.4
g
H
2
O
=
2
×
number of moles of
H
2
O
=
18
2
×
5.4
=
0.6
g
Weight of carbon + weight of hydrogen
=
2.4
+
0.6
=
3.0
g
=
weight of hydrocarbon.
Hence, it illustrates law of conservation of mass.