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Q.
$3\, g$ of a hydrocarbon on combustion with excess of oxygen produces $8.8 \,g$ of $CO _{2}$ and $5.4 \,g$ of $H _{2} O$ The data illustrates the law of
Some Basic Concepts of Chemistry
Solution:
Amount of carbon in $8.8 \,g \,CO _{2}=12 \times$ number of moles of $CO _{2}=\frac{12 \times 8.8}{44}=2.4\, g$
Amount of hydrogen in $5.4\, g \,H _{2} O$
$=2 \times$ number of moles of $H _{2} O =\frac{2 \times 5.4}{18}=0.6 \,g$
Weight of carbon + weight of hydrogen
$=2.4+0.6=3.0 \,g =$ weight of hydrocarbon.
Hence, it illustrates law of conservation of mass.