28 g of N2 and 6 g of H2 were mixed. At equilibrium, 17 g NH3 was produced. The weights of N2 and H2 at equilibrium are respectively

Question

28 g of N2 and 6 g of H2 were mixed. At equilibrium, 17 g NH3 was produced. The weights of N2 and H2 at equilibrium are respectively (A) 11 g, 0 g (B) 1 g, 3 g (C) 14 g, 3 g (D) 11 g, 3 g

Tardigrade Admin · Accepted Answer

N 2+3 H 2 2 NH 3 28 g 6 g 34 g ∵ 34 g NH 3 was produced from =28 g N 2 ∴ 17 g NH 3 will be produced from =(28 × 17/34) =14 g N2 Similarly, 17 g of NH 3 will be produced from =(6 × 17/34) =3 g H 2

Q. 28 g of $N_{2}$ and $6 g$ of $H_{2}$ were mixed. At equilibrium, $17 g$ $N H_{3}$ was produced. The weights of $N_{2}$ and $H_{2}$ at equilibrium are respectively

11 g, 0 g

1 g, 3 g

14 g, 3 g

11 g, 3 g

$N_{2} + 3 H_{2} 2 N H_{3}$
$28 g 6 g 34 g$
$∵ 34 g N H_{3}$
was produced from $= 28 g N_{2}$
$∴ 17 g N H_{3}$
will be produced from $= \frac{28 \times 17}{34}$
$= 14 g N_{2}$
Similarly, $17 g$ of $N H_{3}$
will be produced from $= \frac{6 \times 17}{34}$
$= 3 g H_{2}$

Q. 28 g of N2​ and 6g of H2​ were mixed. At equilibrium, 17g NH3​ was produced. The weights of N2​ and H2​ at equilibrium are respectively