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Q. 28 g of $ {{N}_{2}} $ and $6\,g$ of $ {{H}_{2}} $ were mixed. At equilibrium, $17\,g$ $ N{{H}_{3}} $ was produced. The weights of $ {{N}_{2}} $ and $ {{H}_{2}} $ at equilibrium are respectively

AMUAMU 2014Equilibrium

Solution:

$N _{2}+3 H _{2} 2 NH _{3}$
$28 \,g \,6 \,g \,34\, g$
$\because 34 \, g \, NH _{3}$
was produced from $=28 g N _{2}$
$\therefore 17 \, g \, NH _{3}$
will be produced from $=\frac{28 \times 17}{34}$
$=14 \, g\, N_{2}$
Similarly, $17 \, g$ of $NH _{3}$
will be produced from $=\frac{6 \times 17}{34}$
$=3 \, g\, H _{2}$