Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
25 g of 80 % pure calcium carbonate is treated with excess of HCl . What is the volume of CO2 obtained at NTP in the reaction? CaCO3+2HCl arrow CaCl2+H2O+CO2
Q.
25
g
of
80%
pure calcium carbonate is treated with excess of
H
Cl
. What is the volume of
C
O
2
obtained at
NTP
in the reaction?
C
a
C
O
3
+
2
H
Cl
→
C
a
C
l
2
+
H
2
O
+
C
O
2
330
160
NTA Abhyas
NTA Abhyas 2022
Report Error
A
2.24
L
B
5.6
L
C
11.2
L
D
4.48
L
Solution:
....