Q.
$25\,g$ of $80\%$ pure calcium carbonate is treated with excess of $HCl$ . What is the volume of $CO_{2}$ obtained at $NTP$ in the reaction?
$CaCO_{3}+2HCl \rightarrow CaCl_{2}+H_{2}O+CO_{2}$
NTA AbhyasNTA Abhyas 2022
Solution: