text25 textml of text2 textN textHCl, text50 textml of text4 textN HNO3 and textv textml of text2 textM H2SO4 are mixed together and the total volume is made up to text1 textL after dilution text50 textml of this acid mixture completely reacted with 25 textml of a text1 textN Na2CO3 solution. The value of textv is

Question

text25 textml of text2 textN textHCl, text50 textml of text4 textN HNO3 and textv textml of text2 textM H2SO4 are mixed together and the total volume is made up to text1 textL after dilution text50 textml of this acid mixture completely reacted with 25 textml of a text1 textN Na2CO3 solution. The value of textv is (A) 250 ml (B) 62.5 ml (C) 100 ml (D) 125 ml

Tardigrade Admin · Accepted Answer

aqeous solution Na2CO3 is basic in nature Milli equivalents of acids = milli equivalents of Na2CO3 ⇒ (2 × 25 + 4 × 50 + 4 × x)× (50/1000)=25× 1 ∴ x=62.5 ml

Q. $25 ml$ of $2 N HCl,$ $50 ml$ of $4 N$ $H N O_{3}$ and $v ml$ of $2 M$ $H_{2} S O_{4}$ are mixed together and the total volume is made up to $1 L$ after dilution $50 ml$ of this acid mixture completely reacted with $25 ml$ of a $1 N$ $N a_{2} C O_{3}$ solution. The value of $v$ is

250 ml

62.5 ml

100 ml

125 ml

aqeous solution $N a_{2} C O_{3}$ is basic in nature

Milli equivalents of acids = milli equivalents of $N a_{2} C O_{3}$

$\Rightarrow (2 \times 25 + 4 \times 50 + 4 \times x) \times \frac{50}{1000} = 25 \times 1$

$∴ x = 62.5 m l$

Q. 25ml of 2NHCl, 50ml of 4N HNO3​ and vml of 2M H2​SO4​ are mixed together and the total volume is made up to 1L after dilution 50ml of this acid mixture completely reacted with 25ml of a 1N Na2​CO3​ solution. The value of v is