Question

$\text{25} \, \text{ml}$ of $\text{2} \, \text{N} \, \text{HCl,}$ $\text{50} \, \text{ml}$ of $\text{4} \, \text{N}$ $HNO_{3}$ and $\text{v} \, \text{ml}$ of $\text{2} \, \text{M}$ $H_{2}SO_{4}$ are mixed together and the total volume is made up to $\text{1} \, \text{L}$ after dilution $\text{50} \, \text{ml}$ of this acid mixture completely reacted with $25 \, \text{ml}$ of a $\text{1} \, \text{N}$ $Na_{2}CO_{3}$ solution. The value of $\text{v}$ is

• A. 250 ml
• B. 62.5 ml
• C. 100 ml
• D. 125 ml

Answer 1

Answer: (B)

aqeous solution $Na_{2}CO_{3}$ is basic in nature

Milli equivalents of acids = milli equivalents of $Na_{2}CO_{3}$

$\Rightarrow \left(2 \times 25 + 4 \times 50 + 4 \times x\right)\times \frac{50}{1000}=25\times 1$

$\therefore x=62.5 \, ml$