2 moles of non-volatile solute is added to 1 kg water at -8° C . Kf of water is 2 K textkg mol- 1. Mass of ice that separates out is (Ignoring the effect of change in volume)

Question

2 moles of non-volatile solute is added to 1 kg water at -8° C . Kf of water is 2 K textkg mol- 1. Mass of ice that separates out is (Ignoring the effect of change in volume) (A) 250 g (B) 500 g (C) 750 g (D) 100 g

Tardigrade Admin · Accepted Answer

For no freezing to take place at -8° C , 4 moles solute should be added to 1 kg water but, since 2 mole solute only is available it can stop the freezing of 500 g water only. 500 g ice is formed.

Q. $2$ moles of non-volatile solute is added to $1$ $k g$ water at $- 8^{\circ} C$ . $K_{f}$ of water is $2$ $K kg$ $m o l^{- 1} .$ Mass of ice that separates out is (Ignoring the effect of change in volume)

$250$ $g$

$500$ $g$

$750$ $g$

$100$ $g$

For no freezing to take place at $- 8^{\circ} C$ , $4 m o l es$ solute should be added to $1 k g$ water but, since $2 m o l e$ solute only is available it can stop the freezing of $500$ $g$ water only. $500 g$ ice is formed.

Q. 2 moles of non-volatile solute is added to 1 kg water at −8∘C . Kf​ of water is 2 Kkg mol−1. Mass of ice that separates out is (Ignoring the effect of change in volume)

250 g

500 g

750 g

100 g