+2 C and +6 C two charges are repelling each other with a force of 12 N.If a charge of - 2 C is added to each of them, then the value of the force will be

Question

+2 C and +6 C two charges are repelling each other with a force of 12 N.If a charge of - 2 C is added to each of them, then the value of the force will be (A) 4N (Attractive) (B) 4N (Repulsive) (C) 8N (Repulsive) (D) Zero

Tardigrade Admin · Accepted Answer

Resultant charges after adding the -2 C be (-2+2)=0 and (-2+6)=+4 C ⇒ F =(k Q Q1 Q2/r2)=k × (0 × 4/r2)=0

Q. $+ 2 C$ and $+ 6 C$ two charges are repelling each other with a force of $12 N$ .If a charge of $-$ $2 C$ is added to each of them, then the value of the force will be

4N (Attractive)

4N (Repulsive)

8N (Repulsive)

Zero

Resultant charges after adding the $- 2 C$ be $(- 2 + 2) = 0$ and $(- 2 + 6) = + 4 C$
$\Rightarrow F = \frac{k Q Q _{1} Q _{2}}{r ^{2}} = k \times \frac{0 \times 4}{r ^{2}} = 0$

Q. +2C and +6C two charges are repelling each other with a force of 12N.If a charge of − 2C is added to each of them, then the value of the force will be